document.write( "Question 292981: I have tried several times to figure this one out...Any help with this would be greatly appreciated! Thanks!\r
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\n" ); document.write( "\n" ); document.write( "The weight of an object on a small planet in Alpha Centauri is governed by the following equation:\r
\n" ); document.write( "\n" ); document.write( "w=c*r^-1/2
\n" ); document.write( "Here, C is a constant, and r is the distance that the object is from the center of the planet.
\n" ); document.write( "Solve the above equation for r.
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Algebra.Com's Answer #211506 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"w=c%2Ar%5E%28-1%2F2%29%5E%22%22\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"w%2Fc=r%5E%28-1%2F2%29%5E%22%22\" Divide both sides by 'c'\r
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\n" ); document.write( "\n" ); document.write( "\"w%2Fc=1%2Fr%5E%281%2F2%29%5E%22%22\" Rewrite \"r%5E%28-1%2F2%29%5E%22%22\" as \"1%2Fr%5E%281%2F2%29%5E%22%22\"\r
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\n" ); document.write( "\n" ); document.write( "\"w%2Fc=1%2Fsqrt%28r%29\" Rewrite \"r%5E%281%2F2%29%5E%22%22\" into \"sqrt%28r%29\" (ie convert to radical notation)\r
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\n" ); document.write( "\n" ); document.write( "\"w%2Asqrt%28r%29=c\" Cross multiply\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28r%29=c%2Fw\" Divide both sides by 'w'\r
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\n" ); document.write( "\n" ); document.write( "\"r=%28c%2Fw%29%5E2\" Square both sides to isolate 'r'.\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"r=%28c%2Fw%29%5E2\" which can also be written as \"r=%28c%5E2%29%2F%28w%5E2%29\"
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