document.write( "Question 34886: A circular table is placed into the corner of a room, touching both walls which are perpendicular to each other. A point on the edge (circumference) of the table is one foot from one wall and six inches from the other wall. What is the diameter of the table? \n" ); document.write( "

Algebra.Com's Answer #21147 by venugopalramana(3286) $\"\"$ $\"About$

You can put this solution on YOUR website!
A circular table is placed into the corner of a room, touching both walls which are perpendicular to each other. A point on the edge (circumference) of the table is one foot from one wall and six inches from the other wall. What is the diameter of the table?
\n" ); document.write( "TAKE CORNER AS ORIGIN AND THE 2 PERPENDICULAR WALLS AS X AND Y AXES.SO IF THE RADIUS OF THE CIRCLE IS R ,THEN SINCE THE 2 WALLS/AXES ARE TOUCHIG THE CIRCLE ,THE CNTRE OF THE CIRCLE IS (R,R)
\n" ); document.write( "HENCE EN OF CIRCLE IS
\n" ); document.write( "(X-R)^2+(Y-R)^2=R^2.....THE COORDINATES OF A POINT ON THE CIRCLE IS (12,6).SO
\n" ); document.write( "(12-R)^2+(6-R)^2=R^2
\n" ); document.write( "144-24R+R^2+36-12R+R^=R^2
\n" ); document.write( "R^2-36+180=0
\n" ); document.write( "(R-30)(R-6)=0
\n" ); document.write( "HENCE R=30\"...OR...6\"
\n" ); document.write( "SO DIAMETER IS 60\"=5'...OR......12\"=1' \n" ); document.write( "

\n" );