document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=292771>Question 292771</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve the equation by completing the square, w^2-14w+24=0 ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #211402 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=211402\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  w^2-14w+24=0\r<BR>\n" );
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document.write( "1.) w^2 - 14w = -24\r<BR>\n" );
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document.write( "We need to add the same constant to both sides to get the left side to factor into (x-a)^2 \r<BR>\n" );
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document.write( "If we take half the coefficent on w (that is -14) and then square it we will have the constant we are looking for. -14/2 = -7. If we square -7 we get 49. So we will add 49 to both sides of 1.):\r<BR>\n" );
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document.write( "w^2 - 14w + 49 = -24 + 49<BR>\n" );
document.write( "(w-7)^2 = 25\r<BR>\n" );
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document.write( "w-7 = sqrt(25) or w-7 = -sqrt(25)\r<BR>\n" );
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document.write( "w-7 = 5 or w-7 = -5\r<BR>\n" );
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document.write( "w = 12 or w = 2\r<BR>\n" );
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