document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=292730>Question 292730</A>: <I><SPAN STYLE=\"word-break: break-all;\"> my question say's that the square root of 12 minus the square root of 3 equals k multiplied by the square root of three and wants me to find what k would equal. can you explain how to find k </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #211376 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=211376\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2812%29-sqrt%283%29=k%2Asqrt%283%29 ALIGN=MIDDLE  ALT=\"sqrt%2812%29-sqrt%283%29=k%2Asqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Start with the given equation.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%284%2A3%29-sqrt%283%29=k%2Asqrt%283%29 ALIGN=MIDDLE  ALT=\"sqrt%284%2A3%29-sqrt%283%29=k%2Asqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Factor 12 into 4*3. Note: 4 is a perfect square.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%284%29%2Asqrt%283%29-sqrt%283%29=k%2Asqrt%283%29 ALIGN=MIDDLE  ALT=\"sqrt%284%29%2Asqrt%283%29-sqrt%283%29=k%2Asqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Break up the first root.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2Asqrt%283%29-sqrt%283%29=k%2Asqrt%283%29 ALIGN=MIDDLE  ALT=\"2%2Asqrt%283%29-sqrt%283%29=k%2Asqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Take the square root of 4 to get 2.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282-1%29%2Asqrt%283%29=k%2Asqrt%283%29 ALIGN=MIDDLE  ALT=\"%282-1%29%2Asqrt%283%29=k%2Asqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Factor out the GCF <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%283%29 ALIGN=MIDDLE  ALT=\"sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2Asqrt%283%29=k%2Asqrt%283%29 ALIGN=MIDDLE  ALT=\"1%2Asqrt%283%29=k%2Asqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Combine like terms.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1=k ALIGN=MIDDLE  ALT=\"1=k\"   DISABLED_style= \"max-width:90%; height:auto;\" > Divide both sides by <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%283%29 ALIGN=MIDDLE  ALT=\"sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > to isolate 'k'.\r<BR>\n" );
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document.write( "So we can see that the solution is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=k=1 ALIGN=MIDDLE  ALT=\"k=1\"   DISABLED_style= \"max-width:90%; height:auto;\" > which essentially means that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2812%29-sqrt%283%29=1%2Asqrt%283%29 ALIGN=MIDDLE  ALT=\"sqrt%2812%29-sqrt%283%29=1%2Asqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > or more simply <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2812%29-sqrt%283%29=sqrt%283%29 ALIGN=MIDDLE  ALT=\"sqrt%2812%29-sqrt%283%29=sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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