document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=292638>Question 292638</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a#b=a/b+b/a what is the value of (3#2)-(2#3)? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #211350 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=211350\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First compute 3#2: \r<BR>\n" );
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document.write( "3#2=3/2+2/3=9/6+4/6=13/6\r<BR>\n" );
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document.write( "and now compute 2#3: \r<BR>\n" );
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document.write( "2#3=2/3+3/2=4/6+9/6=13/6\r<BR>\n" );
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document.write( "So (3#2)-(2#3)=(13/6)-(13/6)=0/6=0<BR>\n" );
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