document.write( "Question 34922: I have been on this for hours, if any one can please direct me.\r
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document.write( "A polynomial f(t) of degree 3 satisfies f(−2) = 0, f(2) = 4, f'(−1) = 2, and f'(1) = −6.\r
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document.write( "(a) Write the general form of the polynomial and its derivative.\r
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document.write( "(b) Find four linear equations that must be satisfied by the unknown coefficients in the polynomial.\r
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document.write( "(c) Write the augmented matrix for your system of equations in (b) and row-reduce. \n" );
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Algebra.Com's Answer #21135 by venugopalramana(3286) You can put this solution on YOUR website! I have been on this for hours, if any one can please direct me. \n" ); document.write( "A polynomial f(t) of degree 3 satisfies f(−2) = 0, f(2) = 4, f'(−1) = 2, and f'(1) = −6. \n" ); document.write( "(a) Write the general form of the polynomial and its derivative. \n" ); document.write( "(b) Find four linear equations that must be satisfied by the unknown coefficients in the polynomial. \n" ); document.write( "(c) Write the augmented matrix for your system of equations in (b) and row-reduce. \n" ); document.write( " THE GENERAL FORM OF POLYNOMIAL OF DEGREE 3 IS \n" ); document.write( "F(T)= AT^3+BT^2+CT+D ....................EQN.A \n" ); document.write( "DF/DT= 3AT^2+2BT+C...................EQN.B \n" ); document.write( "WE ARE GIVEN F(-2)=0...SO SUBSTITUTING IN EQN.A \n" ); document.write( "-8A+4B-2C+D=0.............................EQN.I \n" ); document.write( "F(2)=4...SO SUBSTITUTING IN EQN.A \n" ); document.write( "8A+4B+2C+D=4................................EQN.II \n" ); document.write( "F'(-1)=2...SO SUBSTITUTING IN EQN.B \n" ); document.write( "3A-2B+C=2......................................EQN.III \n" ); document.write( "F'(1)=-6...SO SUBSTITUTING IN EQN.B \n" ); document.write( "3A+2B+C=-6..................................EQN.IV \n" ); document.write( "AUGMENTED MATRIX A IS \n" ); document.write( "-8,4,-2,1,0 \n" ); document.write( "8,4,2,1,4 \n" ); document.write( "3,-2,1,0,2 \n" ); document.write( "3,2,1,0,-6 \n" ); document.write( "I HOPE YOU CAN REDUCE THIS NOW AS YOU WANTED DIRECTION ...IF IN DOUBT SEE FOLLOWING EXAMPLE TO KNOW THE METHOD. \n" ); document.write( "---------------------------------------------------------------------- \n" ); document.write( "The problem: \n" ); document.write( "2x-5y+ ___=-22 \n" ); document.write( "__+y+3z=10 \n" ); document.write( "x+___+8z=15 \n" ); document.write( "The underscores represents blanks or O \n" ); document.write( "If this had to be an augmented matrix, how would I do that and get those variables? \n" ); document.write( "1 solutions \n" ); document.write( "Answer 20202 by venugopalramana(1462) About Me on 2006-04-16 22:01:33 (Show Source): \n" ); document.write( "2x-5y+ ___=-22...........................I \n" ); document.write( "__+y+3z=10.....................II \n" ); document.write( "x+___+8z=15...........................III \n" ); document.write( "2*EQN.III-EQN.I \n" ); document.write( "2X+16Z-2X+5Y=30+22=52 \n" ); document.write( "5Y+16Z=52...........................IV \n" ); document.write( "EQN.IV-5*EQN.II \n" ); document.write( "5Y+16Z-5Y-15Z=52-50=2 \n" ); document.write( "Z=2....SUBSTITUTING IN EQN.III \n" ); document.write( "X+8*2=15 \n" ); document.write( "X=15-16=-1 \n" ); document.write( "SUBSTITUTING FOR Z IN EQN.II \n" ); document.write( "Y+3*2=10 \n" ); document.write( "Y=10-6=4 \n" ); document.write( "USING MATRIX METHOD...AUGMENTED MATRIX IS \n" ); document.write( "2 -5 0 -22 1 0 0 ? \n" ); document.write( "0 1 3 10 0 1 0 ? \n" ); document.write( "1 0 8 15 0 0 1 ? \n" ); document.write( "NR1=R1/2 \n" ); document.write( "1 -2.5 0 -11 \n" ); document.write( "0 1 3 10 \n" ); document.write( "1 0 8 15 \n" ); document.write( "NR3=R3-R1 \n" ); document.write( "1 -2.5 0 -11 \n" ); document.write( "0 1 3 10 \n" ); document.write( "0 2.5 8 26 \n" ); document.write( "NR3=R3-2.5*R2 \n" ); document.write( "1 -2.5 0 -11 \n" ); document.write( "0 1 3 10 \n" ); document.write( "0 0 0.5 1 \n" ); document.write( "NR3=R3/0.5 \n" ); document.write( "1 -2.5 0 -11 \n" ); document.write( "0 1 3 10 \n" ); document.write( "0 0 1 2 \n" ); document.write( "NR2=R2-3R3 \n" ); document.write( "1 -2.5 0 -11 \n" ); document.write( "0 1 0 4 \n" ); document.write( "0 0 1 2 \n" ); document.write( "NR1=R1+2.5R2 \n" ); document.write( "1 0 0 -1 \n" ); document.write( "0 1 0 4 \n" ); document.write( "0 0 1 2 \n" ); document.write( "HENCE \n" ); document.write( "X=-1 \n" ); document.write( "Y=4 \n" ); document.write( "Z=2 \n" ); document.write( " |