document.write( "Question 292650: What are the coordinates of the turning point for the graph of the parabola whose equation is y=2x^2+4x-7? \n" ); document.write( "
Algebra.Com's Answer #211346 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
We essentially want to convert the equation into vertex form. To do that, we need to complete the square. Note: the vertex of the parabola is the turning point.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2x%5E2%2B4x-7\" Start with the given expression.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2%28x%5E2%2B2x-7%2F2%29\" Factor out the \"x%5E2\" coefficient \"2\". This step is very important: the \"x%5E2\" coefficient must be equal to 1.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Take half of the \"x\" coefficient \"2\" to get \"1\". In other words, \"%281%2F2%29%282%29=1\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now square \"1\" to get \"1\". In other words, \"%281%29%5E2=%281%29%281%29=1\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2%28x%5E2%2B2x%2Bhighlight%281-1%29-7%2F2%29\" Now add and subtract \"1\" inside the parenthesis. Make sure to place this after the \"x\" term. Notice how \"1-1=0\". So the expression is not changed.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2%28%28x%5E2%2B2x%2B1%29-1-7%2F2%29\" Group the first three terms.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2%28%28x%2B1%29%5E2-1-7%2F2%29\" Factor \"x%5E2%2B2x%2B1\" to get \"%28x%2B1%29%5E2\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2%28%28x%2B1%29%5E2-9%2F2%29\" Combine like terms.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2%28x%2B1%29%5E2%2B2%28-9%2F2%29\" Distribute.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2%28x%2B1%29%5E2-9\" Multiply.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So after completing the square, \"2x%5E2%2B4x-7\" transforms to \"2%28x%2B1%29%5E2-9\". So \"2x%5E2%2B4x-7=2%28x%2B1%29%5E2-9\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So \"2x%5E2%2B4x-7=0\" is equivalent to \"2%28x%2B1%29%5E2-9=0\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So \"y=2x%5E2%2B4x-7\" is equivalent to \"y=2%28x%2B1%29%5E2-9\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the equation \"y=2%28x%2B1%29%5E2-9\" is now in vertex form \"y=a%28x-h%29%5E2%2Bk\" where \"a=2\", \"h=-1\", and \"k=-9\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Remember, the vertex of \"y=a%28x-h%29%5E2%2Bk\" is (h,k).\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the vertex of \"y=2%28x%2B1%29%5E2-9\" is (-1,-9). \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "This consequently means that the vertex of \"y=2x%5E2%2B4x-7\" is (-1,-9) (since the two equations are equivalent) \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the turning point of \"y=2x%5E2%2B4x-7\" is (-1,-9)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );