document.write( "Question 292613: The math problem says solve for 'X'
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\n" ); document.write( "\n" ); document.write( "i had to subract from both sides\r
\n" ); document.write( "\n" ); document.write( "5x^2-3x-1=1-1
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\n" ); document.write( "it says i have to apply the quadratic formula. Once i plugged my numbers in for -4AC it says its wrong.. how do i plugg them in ? so i can finnish solivng the rest of the equation.
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Algebra.Com's Answer #211312 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "When you get here:\r\n" );
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document.write( "\"5x%5E2-3x-1=0\"\r\n" );
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document.write( "Compare that to\r\n" );
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document.write( "\"ax%5E2%2Bbx%2Bc=0\"\r\n" );
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document.write( "and you can see that \"a=5\", \"%22%22%2Bb=-3\" and \"%22%22%2Bc=-1\"\r\n" );
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document.write( "Then you write\r\n" );
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document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"\r\n" );
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document.write( "Now substitute \"%285%29\" for \"a\", \"%28-3%29\" for \"b\", and \"%28-1%29\" for c\r\n" );
document.write( "in that equation, and when you do you get:\r\n" );
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document.write( "Then you simplify that:\r\n" );
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document.write( "\"x+=+%283+%2B-+sqrt%289%2B20+%29%29%2F10+\"\r\n" );
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document.write( "\"x+=+%283+%2B-+sqrt%2829+%29%29%2F10+\"\r\n" );
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document.write( "So you have two solutions.\r\n" );
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document.write( "Solution 1 has a + where the ± is\r\n" );
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document.write( "\"x+=+%283+%2B+sqrt%2829%29%29%2F10+\"\r\n" );
document.write( "Then use your calculator to get the approximation for solution 1:\r\n" );
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document.write( "Solution 2 has a - where the ± is\r\n" );
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document.write( "\"x+=+%283+-+sqrt%2829%29%29%2F10+\"\r\n" );
document.write( "Then use your calculator to get the approximation for solution 2:\r\n" );
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document.write( "Edwin
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