document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=292546>Question 292546</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Will someone please tell me if my calculation are corrct for the following problem? Thank you.\r<BR>\n" );
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document.write( "(3x+3w+bx+bw)/(x^2-w^2 )÷(9-b^2)/(6-2b)<BR>\n" );
document.write( "=(3(x+w)+ b(x+w))/((x+w)(x-w)) ÷ ((3+b)(3-b))/(2(3-b))\r<BR>\n" );
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document.write( "= (3+b)/(x-w) ÷ (3+b)/2\r<BR>\n" );
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document.write( "= (6+2b)/(3x+xb-3w-bw)\r<BR>\n" );
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document.write( "= (2(3+b))/(x(3+b)  – w(3-b))\r<BR>\n" );
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document.write( "= 2/((x-w)(3-b))<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #211302 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=211302\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2/(x-w)<BR>\n" );
document.write( "You got lost after (3+b)/(x-w) ÷ (3+b)/2 <BR>\n" );
document.write( "Remember that dividing is the same as multiplying by the reciprocal.<BR>\n" );
document.write( "so we flip the second part and multiply<BR>\n" );
document.write( "(3+b)/(x-w) *2/(3+b)  </SPAN>\n" );
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