document.write( "Question 292600: Henry invested $12,000 in a new
\n" ); document.write( "restaurant. When the restaurant was sold two years
\n" ); document.write( "later, he received $27,000. Find his average annual
\n" ); document.write( "return by solving the equation 12,000(1  r)2 
\n" ); document.write( "27,000.
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Algebra.Com's Answer #211298 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
F = P * (1+i)^n\r
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\n" ); document.write( "\n" ); document.write( "F = 27000
\n" ); document.write( "P = 12000
\n" ); document.write( "i = what you want to find.
\n" ); document.write( "n = 2 years\r
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\n" ); document.write( "\n" ); document.write( "Plug your values into this equation to get:\r
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\n" ); document.write( "\n" ); document.write( "27000 = 12000 * \"%281%2Bi%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides of this equation by 12000 to get:\r
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\n" ); document.write( "\n" ); document.write( "\"27000%2F12000\" = \"%281%2Bi%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Simplify to get:\r
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\n" ); document.write( "\n" ); document.write( "2.25 = \"%281%2Bi%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Take the square root of both sides of this equation to get:\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%282.25%29\" = 1+i\r
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\n" ); document.write( "\n" ); document.write( "Simplify to get:\r
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\n" ); document.write( "\n" ); document.write( "1.5 = 1+i\r
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\n" ); document.write( "\n" ); document.write( "Subtract 1 from both aides of the equation to get:\r
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\n" ); document.write( "\n" ); document.write( "i = .5\r
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\n" ); document.write( "\n" ); document.write( "That's a 50% growth rate per year.\r
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\n" ); document.write( "\n" ); document.write( "Plug that value into your original equation to get:\r
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\n" ); document.write( "\n" ); document.write( "27000 = 12000 * \"%281%2Bi%29%5E2\" becomes:\r
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\n" ); document.write( "\n" ); document.write( "27000 = 12000 * \"%281.5%29%5E2\" which becomes:\r
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\n" ); document.write( "\n" ); document.write( "27000 = 12000 * 2.25 which becomes:\r
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\n" ); document.write( "\n" ); document.write( "27000 = 27000 confirming that the value of .5 interest rate of growth per year is accurate.\r
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\n" ); document.write( "\n" ); document.write( "Your answer is that his average annual rate of return is 50%.\r
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