document.write( "Question 292496: solution of 4s^3+12s^2+12s+4=0 \n" ); document.write( "
Algebra.Com's Answer #211253 by richwmiller(17219)\"\" \"About 
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4s^3+12s^2+12s+4=0
\n" ); document.write( "factor out 4
\n" ); document.write( "4*(s^3+3s^2+3s+1)=0
\n" ); document.write( "from this we see that the zeros are factors of 1
\n" ); document.write( "4*(s+1)^3=0
\n" ); document.write( "s=-1\r
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