document.write( "Question 292458: Joe had nickles and dimes worth $6.30. If the dimes were doubled and the number of nickles increased by 15, the value of the coins would be $10.75. How many dimes does he have? \n" ); document.write( "
Algebra.Com's Answer #211249 by ankor@dixie-net.com(22740)\"\" \"About 
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Let n = original no. of nickels
\n" ); document.write( "Let d = original no. of dimes
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\n" ); document.write( "Write an equation for each statement:
\n" ); document.write( ":
\n" ); document.write( "Joe had nickles and dimes worth $6.30.
\n" ); document.write( ".05n + .10d = 6.30
\n" ); document.write( ":
\n" ); document.write( " If the dimes were doubled and the number of nickles increased by 15,
\n" ); document.write( " the value of the coins would be $10.75.
\n" ); document.write( ".05(n+15) + 2(.10d) = 10.75
\n" ); document.write( ".05n + .75 + .20d = 10.75
\n" ); document.write( ".05n + .20d = 10.75 -.75
\n" ); document.write( ".05n + .20d = 10.00
\n" ); document.write( ":
\n" ); document.write( "We can use elimination here, subtract the 1st equation from the above equation
\n" ); document.write( ".05n + .20d = 10.00
\n" ); document.write( ".05n + .10d = 6.30
\n" ); document.write( "----------------------subtraction eliminates n, find d
\n" ); document.write( ".10d = 3.70
\n" ); document.write( "d = \"3.7%2F.1\"
\n" ); document.write( "d = 37 dimes
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\n" ); document.write( "Check solution.
\n" ); document.write( "Find the no. of nickels
\n" ); document.write( ".05n + .10(37) = 6.30
\n" ); document.write( ".05n = 6.30 - 3.70
\n" ); document.write( ".05n = 2.60
\n" ); document.write( "n = \"2.6%2F.05\"
\n" ); document.write( "n = 52 nickels
\n" ); document.write( "then
\n" ); document.write( ".05(52) = .10(37)
\n" ); document.write( "2.60 + 3.70 = 6.30; confirms our solution\r
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