document.write( "Question 292458: Joe had nickles and dimes worth $6.30. If the dimes were doubled and the number of nickles increased by 15, the value of the coins would be $10.75. How many dimes does he have? \n" ); document.write( "
Algebra.Com's Answer #211249 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Let n = original no. of nickels \n" ); document.write( "Let d = original no. of dimes \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement: \n" ); document.write( ": \n" ); document.write( "Joe had nickles and dimes worth $6.30. \n" ); document.write( ".05n + .10d = 6.30 \n" ); document.write( ": \n" ); document.write( " If the dimes were doubled and the number of nickles increased by 15, \n" ); document.write( " the value of the coins would be $10.75. \n" ); document.write( ".05(n+15) + 2(.10d) = 10.75 \n" ); document.write( ".05n + .75 + .20d = 10.75 \n" ); document.write( ".05n + .20d = 10.75 -.75 \n" ); document.write( ".05n + .20d = 10.00 \n" ); document.write( ": \n" ); document.write( "We can use elimination here, subtract the 1st equation from the above equation \n" ); document.write( ".05n + .20d = 10.00 \n" ); document.write( ".05n + .10d = 6.30 \n" ); document.write( "----------------------subtraction eliminates n, find d \n" ); document.write( ".10d = 3.70 \n" ); document.write( "d = \n" ); document.write( "d = 37 dimes \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution. \n" ); document.write( "Find the no. of nickels \n" ); document.write( ".05n + .10(37) = 6.30 \n" ); document.write( ".05n = 6.30 - 3.70 \n" ); document.write( ".05n = 2.60 \n" ); document.write( "n = \n" ); document.write( "n = 52 nickels \n" ); document.write( "then \n" ); document.write( ".05(52) = .10(37) \n" ); document.write( "2.60 + 3.70 = 6.30; confirms our solution\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |