document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=292470>Question 292470</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a triangle has a base of 2x+1 and a height of 6x-3. What value of X would give and Area of 240 m^2.\r<BR>\n" );
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document.write( "Please help me on how to put this into an equation and solve it. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #211247 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=211247\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If a triangle has a base of 2x+1 and a height of 6x-3. What value of X would give and Area of 240 m^2. <BR>\n" );
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document.write( "Area of any triangle is (1/2)bh<BR>\n" );
document.write( "where<BR>\n" );
document.write( "b is base<BR>\n" );
document.write( "h is height<BR>\n" );
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document.write( "In your case then:<BR>\n" );
document.write( "(1/2)(2x+1)(6x-3) = 240<BR>\n" );
document.write( "multiplying both sides by 2:<BR>\n" );
document.write( "(2x+1)(6x-3) = 480<BR>\n" );
document.write( "FOIL the left side:<BR>\n" );
document.write( "12x^2 - 6x + 6x - 3 = 480<BR>\n" );
document.write( "12x^2 - 3 = 480<BR>\n" );
document.write( "12x^2 = 483<BR>\n" );
document.write( "x^2 = 483/12<BR>\n" );
document.write( "x = 6.3443 </SPAN>\n" );
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