document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=292483>Question 292483</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 37-inch-square TV is on sale at the local electronics store. If 37 inches is the measure of the diagonal of the screen, use the Pythagorean theorem to find the length of the side of the screen. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #211244 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=211244\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     A 37-inch-square TV is on sale at the local electronics store. If 37 inches is the measure of the diagonal of the screen, use the Pythagorean theorem to find the length of the side of the screen.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Let x = length of the side of the screen<BR>\n" );
document.write( "then<BR>\n" );
document.write( "x^2 + x^2 = 37^2<BR>\n" );
document.write( "2x^2 = 37^2<BR>\n" );
document.write( "2x^2 = 1369<BR>\n" );
document.write( "x^2 = 1369/2<BR>\n" );
document.write( "x = sqrt(1369/2)<BR>\n" );
document.write( "x = 26.163 inches </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );