document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=292482>Question 292482</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you calculate the value of x in a right triangle with legs of x and 2x-1 and a hypoyenuse of 2x-1?  I have tried the pythagorean theorem but x = 0.  I don't think it works because the leg and the hypotenuse are the same. Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #211242 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=211242\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse is the longest side. There can't be a side equal to it.<BR>\n" );
document.write( "check the problem<BR>\n" );
document.write( "Perhaps the hypotenuse is 2x+1.<BR>\n" );
document.write( "x^2+(2x-1)^2=(2x+1)^2<BR>\n" );
document.write( "x=8 or 0 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );