document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=292330>Question 292330</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how to solve -5(4x+8)=-260 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #211206 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=211206\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The short answer is \"methodically.\"<BR>\n" );
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document.write( "-5(4x+8)=-260<BR>\n" );
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document.write( "divide both sides by -5 to get rid of it on the left-hand side, and it will make the right-hand side positive.<BR>\n" );
document.write( "(4x+8) = 52<BR>\n" );
document.write( "4x + 8 = 52<BR>\n" );
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document.write( "subtract 8 from both sides<BR>\n" );
document.write( "4x = 44<BR>\n" );
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document.write( "divide both sides by 4<BR>\n" );
document.write( "x = 11<BR>\n" );
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document.write( "check by substituting back into the original equation<BR>\n" );
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document.write( "-5(4x+8)=-260 ??<BR>\n" );
document.write( "-5(4*11+8) = -5(52) = -260<BR>\n" );
document.write( "correct.<BR>\n" );
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document.write( "Answer:<BR>\n" );
document.write( "x = 11<BR>\n" );
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document.write( "Done. </SPAN>\n" );
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