document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34892>Question 34892</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I still need help in trying to find out how to solve for the square root manually.   I realize that with advent of calculators, this should be easy.  But the prof actually wants us to do it manually.  Example  is square root of 529.  Thank you very much for your help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #21119 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=21119\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ALL SQUARE ROOT NUMBERS NEED TO BE COMBINED IN SETS OF TWO COUNTING FROM THR RIGHT OF THE DECIMAL. FOR YOUR NUMBER THIS WOULD BE 5 & 29.\r<BR>\n" );
document.write( "\n" );
document.write( "FINDING THE SQUARE ROOT OF THIS NUMBER IS A VARIATION ON A DIVISION STRUCTURE.\r<BR>\n" );
document.write( "\n" );
document.write( "FIRST WE FIND THE LARGEST NUMBER WHEN SQUARED IS LESS THAN OR EQUAL TO 5.\r<BR>\n" );
document.write( "\n" );
document.write( "THIS NUMBER IS 2. SQUARING THIS NUMBER AND SUBTRACTING (4) FROM 5 WE GET 1.\r<BR>\n" );
document.write( "\n" );
document.write( "NOW WE BRING DOWN THE NEXT SET (29) AND APPEND THEM TO THE REMAINDER (1). WE \r<BR>\n" );
document.write( "\n" );
document.write( "NOW HAVE 129 AND WE DOUBLE THE 2 FROM THE QUOTION (4) AND DIVIDE 129 BY 4X. \r<BR>\n" );
document.write( "\n" );
document.write( "X BEING THE SECOND DIGIT IN THE NEW DIVISOR. DIVIDING THE 12 BY 4 WE GET 3. \r<BR>\n" );
document.write( "\n" );
document.write( "NOW THE SECOND DIGIT IN THE QUOTION BECOMES A 3 AND THE DIVISOR NOW BECOMES \r<BR>\n" );
document.write( "\n" );
document.write( "23. NOW WE MULTIPLY 3 TIMES 23 AND WE GET 129. SUBTRACTING 129 FROM 129 WE GET \r<BR>\n" );
document.write( "\n" );
document.write( "A REMAINDER OF 0 AND THE ANSWER IS THE QUOTION OF 23. PROVE IT BY MULTIPLYING \r<BR>\n" );
document.write( "\n" );
document.write( "23 TIMES 23. \r<BR>\n" );
document.write( "\n" );
document.write( "HOPE YOU FOLLOWED THIS AS I AM NOT ABLE TO USING THE GRAPHIC/FORMULAR SYSTEM \r<BR>\n" );
document.write( "\n" );
document.write( "YET.      \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );