document.write( "Question 291994: if A does a work in x hrs n b in x+6hrs then how much time will it require if both work together??
\n" ); document.write( "please give explanation of the solution
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Algebra.Com's Answer #211071 by ankor@dixie-net.com(22740)\"\" \"About 
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if A does a work in x hrs, and b in x+6 hrs, then how much time will it require if both work together??
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\n" ); document.write( "let t = time required when they work together
\n" ); document.write( "let the completed job = 1
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\n" ); document.write( "A shared work equation
\n" ); document.write( "\"t%2Fx\" + \"t%2F%28%28x%2B6%29%29\" = 1
\n" ); document.write( "multiply equation by x(x+6), results:
\n" ); document.write( "t(x+6) + xt = x(x+6)
\n" ); document.write( "tx + 6t + xt = x^2 + 6x
\n" ); document.write( "2tx + 6t = x^2 + 6x
\n" ); document.write( "factor out t
\n" ); document.write( "t(2x+6) = x^2 + 6x
\n" ); document.write( "divide both sides by (2x+6)
\n" ); document.write( "t = \"%28x%5E2%2B6x%29%2F%282x%2B6%29\" is the time when they work together (in terms of x)
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\n" ); document.write( "Each one will do a fraction of the work, the two fractions add up to 1 which is the completed job
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