document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=292036>Question 292036</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One # is 5 times another, if the sum of their reciprocals is two-fifths, find the two numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #211042 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=211042\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=one number; reciprocal is 1/x<BR>\n" );
document.write( "Then 5x=the other number; reciprocal is 1/5x<BR>\n" );
document.write( "so:<BR>\n" );
document.write( "1/x + 1/5x=2/5  multiply each term by 5x<BR>\n" );
document.write( "5+1=2x<BR>\n" );
document.write( "2x=6<BR>\n" );
document.write( "x=3 -----one number<BR>\n" );
document.write( "5x=5*3=15----the other number<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "1/3+1/15=2/5<BR>\n" );
document.write( "5/15 +1/15=2/5<BR>\n" );
document.write( "6/15=2/5<BR>\n" );
document.write( "2/5=2/5\r<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps---ptaylor </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );