document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34877>Question 34877</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. Find the radius of a circle with circumference of 20pi.\r<BR>\n" );
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document.write( "2.Find the radius of a circle with the circumference of 64pi\r<BR>\n" );
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document.write( "3.If the area of a circle is 9pi, find the radius.\r<BR>\n" );
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document.write( "4.If the area of a circle is 64 pi, find the circumference.\r<BR>\n" );
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document.write( "help much appreciated. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #21104 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=21104\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> CIR=2*PI*R OR 20*PI=2*PI*R DIVIDING BOTH SIDES BY 2*PI WE GET R=10\r<BR>\n" );
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document.write( "CIR=2*PI*R OR 64*PI=2*PI*R DIVIDING BOTH SIDES BY 2*PI WE GET R=32\r<BR>\n" );
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document.write( "AREA=PI*R~2 OR 9*P1=PI*R~2 DIVIDING BOTH SIDES BY PI WE GET R~2=9 OR R=3\r<BR>\n" );
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document.write( "AREA=PI*R~2 OR 64*PI=PI*R~2 DIVIDING BOTH SIDES BY PI WE GET R~2=54 OR R=8   </SPAN>\n" );
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