document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=291990>Question 291990</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For the points P and Q, find the distance d(P,Q)\r<BR>\n" );
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document.write( "P(-5, -7), Q(-13,1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #211028 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=211028\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let d = distance from P to Q.\r<BR>\n" );
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document.write( "d = sqrt{(-13 + 5)^2 + (1 + 7)^2}\r<BR>\n" );
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document.write( "d = sqrt{(-8)^2 + (8)^2}\r<BR>\n" );
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document.write( "d = sqrt{64 + 64}\r<BR>\n" );
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document.write( "d = sqrt{128}\r<BR>\n" );
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document.write( "d = sqrt{16} * sqrt{8}\r<BR>\n" );
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document.write( "d = 4 * sqrt{4} * sqrt{2}\r<BR>\n" );
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document.write( "d = 4 * 2 * sqrt{2}\r<BR>\n" );
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document.write( "d = 8(sqrt{2}) </SPAN>\n" );
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