document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34876>Question 34876</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 15ft ladder is leaning against a buliding. If the bottom of the ladder is 9ft from the base of the building, how high does the ladder reach?\r<BR>\n" );
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document.write( "I got 17.49 I'm not sure if it's right. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #21102 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=21102\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE LADDER CANNOT REACH HIGHER THAN THE LENGTH OF THE LADDER.\r<BR>\n" );
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document.write( "THE FORMULA FOR THIS PROBLEM IS BASE~2*HEIGHT~2=LENGTH OF THE LADDER~2\r<BR>\n" );
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document.write( "OR 9~2+HEIGHT~2=15~2 OR 81+HEIGHT~2=225 OR HEIGHT~2=225-81 OR HEIGHT~2=144 OR \r<BR>\n" );
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document.write( "HEIGHT IS SQRT OF 144 OR HEIGHT=12 FEET \r<BR>\n" );
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document.write( "THIS IS A STANDARD 3-4-5 OR A 9-12-15 RIGHT TRIANGLE.  <BR>\n" );
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