document.write( "Question 291977: I get points for showing the correct solution and showing the steps. \r
\n" ); document.write( "\n" ); document.write( "2(n - 3) + 5 = 3(n - 1)\r
\n" ); document.write( "\n" ); document.write( "By the way, this is \"Solving Equations with Variables on Both Sides.\" \n" ); document.write( "

Algebra.Com's Answer #211017 by nyc_function(2741) $\"\"$ $\"About$

You can put this solution on YOUR website!
2(n - 3) + 5 = 3(n - 1)\r
\n" ); document.write( "\n" ); document.write( "2n - 6 + 5 = 3n - 3\r
\n" ); document.write( "\n" ); document.write( "2n - 1 = 3n - 3\r
\n" ); document.write( "\n" ); document.write( "2n - 3n = -3 + 1\r
\n" ); document.write( "\n" ); document.write( "-n = -2\r
\n" ); document.write( "\n" ); document.write( "n = -2/-1\r
\n" ); document.write( "\n" ); document.write( "n = 2\r
\n" ); document.write( "\n" ); document.write( "THE PROVE:\r
\n" ); document.write( "\n" ); document.write( "Let n = 2\r
\n" ); document.write( "\n" ); document.write( "2(2 - 3) + 5 = 3(2 - 1)\r
\n" ); document.write( "\n" ); document.write( "2(-1) + 5 = 3(1)\r
\n" ); document.write( "\n" ); document.write( "-2 + 5 = 3\r
\n" ); document.write( "\n" ); document.write( "3 = 3....It checks!!\r
\n" ); document.write( "\n" ); document.write( "The answer is n = 2.\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );