document.write( "Question 291540: A man covers a certain distance on scootr. Had he moved 3kmph faster, he would have taken 40min less,if he had moved 2kmph slower he would have taken 40 min more.The distance in (km)is \n" ); document.write( "
Algebra.Com's Answer #210973 by ankor@dixie-net.com(22740)\"\" \"About 
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A man covers a certain distance on scooter.
\n" ); document.write( "Had he moved 3 kmph faster, he would have taken 40 min less,
\n" ); document.write( "if he had moved 2 kmph slower he would have taken 40 min more.
\n" ); document.write( "The distance in (km)is:
\n" ); document.write( ":
\n" ); document.write( "I don't think there is a unique solution to this, time, speed, and distance
\n" ); document.write( " are all unknown, but we can try and find at least one integer solution
\n" ); document.write( ":
\n" ); document.write( "We can say the faster time is 80 min less than the slower time
\n" ); document.write( "80 min = 80/60 = \"4%2F3\" hrs
\n" ); document.write( "and
\n" ); document.write( "fast speed is 5 mph more than the slow speed
\n" ); document.write( ":
\n" ); document.write( "s = slow speed
\n" ); document.write( "(s+5) = fast speed
\n" ); document.write( ":
\n" ); document.write( "Let d = the distance
\n" ); document.write( ":
\n" ); document.write( "Write a time equation: Time = dist/speed
\n" ); document.write( "slow time - fast time = 4/3 hr
\n" ); document.write( "\"d%2Fs\" - \"d%2F%28%28s%2B5%29%29%7D%7D%29+=+%7B%7B%7B4%2F3\"
\n" ); document.write( "Multiply equation by 3s(s+5), results
\n" ); document.write( "3d(s+5) - 3ds = 4s(s+5)
\n" ); document.write( ":
\n" ); document.write( "3ds + 15d - 3ds = 4s^2 + 20s
\n" ); document.write( ":
\n" ); document.write( "d(3s+15-3s) = 4s^2 + 20s
\n" ); document.write( ":
\n" ); document.write( "d(15) = 4s^2 + 20s
\n" ); document.write( "d = \"%284s%5E2+%2B+20s%29%2F15\"
\n" ); document.write( "One integer solution to d results when s = 10
\n" ); document.write( "d = \"%284%2810%5E2%29+%2B+20%2810%29%29%2F15\"
\n" ); document.write( "d = \"%28400+%2B+200%29%2F15\"
\n" ); document.write( "d = \"600%2F15\"
\n" ); document.write( "d = 40 km is the distance when the slower speed = 10 km/hr
\n" ); document.write( ":
\n" ); document.write( "See if that is true,
\n" ); document.write( "his original speed, 2 mi faster than the slowest speed then s= 12 km/hr
\n" ); document.write( ":
\n" ); document.write( "If he went 3 km/hr faster = 15 km/hr
\n" ); document.write( ":
\n" ); document.write( "Check the time difference when 3 km/hr faster
\n" ); document.write( "\"40%2F12\" - \"40%2F15\" =
\n" ); document.write( "3.33 - 2.66 = .67 hrs; which is .67*60 = 40.2 ~ 40 min
\n" ); document.write( "and when it's 2 km/hr slower
\n" ); document.write( "\"40%2F10\" - \"40%2F12\" =
\n" ); document.write( "4 - 3.33 = .67 hrs; which is .67*60 = 40.2 ~ 40 min
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\n" ); document.write( ":
\n" ); document.write( "Bear in mind this is only one of many solutions
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