document.write( "Question 34865: With the wind, an airplane travels 2200 miles in 4 hours. Against the wind, it takes 5 hours to travel 2350 miles. Find the rate of the plane in still air. \n" ); document.write( "
Algebra.Com's Answer #21091 by Paul(988)\"\" \"About 
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Let the rate of the wind be y
\n" ); document.write( "Let the rate of the plane be x
\n" ); document.write( "Equation 1:
\n" ); document.write( "4x+4y=2200
\n" ); document.write( "y=550-x (subsittuion)
\n" ); document.write( "Equation 2:
\n" ); document.write( "5x-5y=2350
\n" ); document.write( "Apply subsitution:
\n" ); document.write( "5x-5(550-x)=2350
\n" ); document.write( "10x=5100
\n" ); document.write( "x=510
\n" ); document.write( "y=550-510
\n" ); document.write( "y=40
\n" ); document.write( "Hence, the speed of the plane is 510mph and the speed of the wind is 40mph.
\n" ); document.write( "Paul.
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