document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4581>Question 4581</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If r = 5 z then 15 z = 3 y, then r = <BR>\n" );
document.write( "Please explain step by step </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2109 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2109\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If r = 5z, then 15 z = 3y.  \r<BR>\n" );
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document.write( "In the second equation divide both sides by 3.  This gives you:<BR>\n" );
document.write( "If r = 5z, then <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=15z%2F3+=+3y%2F3 ALIGN=MIDDLE  ALT=\"15z%2F3+=+3y%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > or 5z = y.\r<BR>\n" );
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document.write( "Therefore, by Transitive Property of Equations, since r and y both equal 5z,\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+r=y ALIGN=MIDDLE  ALT=\"+r=y\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "R^2 at SCC </SPAN>\n" );
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