document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=291719>Question 291719</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the equation of the circle containing the points J(-3, -3), K(1, -3), and L(1, 1). Show all work to receive credit. <BR>\n" );
document.write( "***can someone please work this out for me i have mutuple problems like this so if i see this one ill be able to do the others thank you sooooooo much!!!\r<BR>\n" );
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document.write( "also you can IM me at smilez750 at aim </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #210893 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=210893\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Write the equation of the circle containing the points J(-3, -3), K(1, -3), and L(1, 1). Show all work to receive credit. <BR>\n" );
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document.write( "If you look at the points, or plot them, you'll see that they from a right triangle.<BR>\n" );
document.write( "In the case of 3 points that make a right triangle, the hypotenuse is the diameter.<BR>\n" );
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document.write( "d = distance from (-3,-3) to (1,1)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d+=+sqrt%284%5E2+%2B+4%5E2%29+=+4sqrt%282%29 ALIGN=MIDDLE  ALT=\"d+=+sqrt%284%5E2+%2B+4%5E2%29+=+4sqrt%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r+=+2sqrt%282%29 ALIGN=MIDDLE  ALT=\"r+=+2sqrt%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "The center of the circle is the midpoint of the same 2 points.  Find it by getting the averages of x and y:<BR>\n" );
document.write( "x: (-3 + 1)/2 = -1<BR>\n" );
document.write( "y is the same<BR>\n" );
document.write( "The center is (-1,-1) and the radius is given above.<BR>\n" );
document.write( "--> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%2B1%29%5E2+%2B+%28y%2B1%29%5E2+=+8 ALIGN=MIDDLE  ALT=\"%28x%2B1%29%5E2+%2B+%28y%2B1%29%5E2+=+8\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "If the points don't make a right triangle, it's more tedious.<BR>\n" );
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