document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=291630>Question 291630</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The access code for a car's security consists of four digits.  The first digit cannot be 3 and the last digit must be odd.  <BR>\n" );
document.write( "1) How many diff codes are available? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #210885 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=210885\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If there were no restrictions, there would be 10000 possible choices from 0000 to 9999. <BR>\n" );
document.write( "Since the first number cannot be 3 then 3000-3999 are not available leaving only 9000 choices. <BR>\n" );
document.write( "The last digit is either even or odd and are evenly distributed so 4500 odds and 4500 evens. <BR>\n" );
document.write( "So that leaves 4500 available codes with the first number not 3 and the last digit not odd.  </SPAN>\n" );
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