document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34777>Question 34777</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having a really hard time understanding the Gauss-Jordan Method.  I have reviewed everything I could possibly find on this subject and it seems like there is no formal way to do this.  I need a method to the madness?  Please help if you can...\r<BR>\n" );
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document.write( "Use the Gauss-Jordan Mathod to solve these systems of linear equations.\r<BR>\n" );
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document.write( "Problem #1:<BR>\n" );
document.write( "x+y+z=5<BR>\n" );
document.write( "y+z=1<BR>\n" );
document.write( "2z=4\r<BR>\n" );
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document.write( "Problem #2:<BR>\n" );
document.write( "x+y=1<BR>\n" );
document.write( "2x+3y=0\r<BR>\n" );
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document.write( "Your explanations of how to understand this method is greatly appreciated.<BR>\n" );
document.write( "Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #21088 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=21088\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> CREATING A MATRIX WE GET\r<BR>\n" );
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document.write( "1  1  1<BR>\n" );
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document.write( "0  1  1 OR1(2-0)-1(0-0)+1(0-0)OR 1*2-1*0+1*0 OR 2-0=0 OR 2 IS THE DENOMINATOR<BR>\n" );
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document.write( "0  0  2\r<BR>\n" );
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document.write( "FOR X WE GET \r<BR>\n" );
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document.write( "5  1  1\r<BR>\n" );
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document.write( "1  1  1 OR 5(2-0)-1(2-4)+1(0-4) OR 10+2-4 OR 8 DIV BY 2 WE GET 8/2=4 FOR X\r<BR>\n" );
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document.write( "4  0  2\r<BR>\n" );
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document.write( "FOR Y WE GET\r<BR>\n" );
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document.write( "1  5  1\r<BR>\n" );
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document.write( "0  1  1 OR 1(2-4)-5(0)+1(0)OR -2-5*0+1*0 OR -2 DIV BY 2 WE GET 2/-2=-1 FOR Y\r<BR>\n" );
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document.write( "0  4  2\r<BR>\n" );
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document.write( "FOR Z WE GET\r<BR>\n" );
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document.write( "1  1  5\r<BR>\n" );
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document.write( "0  1  1 OR 1(4-0)-1(0)+5(0) OR 4-0+0 OR 4 DIV BY 2 WE GET 2 FOR Z   \r<BR>\n" );
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document.write( "0  0  4 \r<BR>\n" );
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document.write( "THUS X=4, Y=-1 & Z=2\r<BR>\n" );
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document.write( "X+Y=1 & 2X+3Y=0 THEN X=1-Y SUBSTITUTING 1-Y FOR X IN EQUATION TWO WE GET\r<BR>\n" );
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document.write( "2(1-Y)+3Y=0 OR 2-2Y+3Y=0 OR 2+Y=0 OR Y=-2 THEN X=1-(-2) OR X=3 \r<BR>\n" );
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document.write( " </SPAN>\n" );
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