document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=291691>Question 291691</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Four times the third of three consecutive odd integers is 6 less than twice the second. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #210879 by </B><A HREF=/tutors/aboutme.mpl?userid=College+Student><B>College Student(505)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=College+Student><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=College+Student><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=210879\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since we need three odd consecutive integers, let:\r<BR>\n" );
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document.write( "x = odd integer<BR>\n" );
document.write( "x+2 = the second odd integer<BR>\n" );
document.write( "x+4 = the third odd integer\r<BR>\n" );
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document.write( "Therefore, the equation becomes: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%28x%2B4%29=2%28x%2B2%29-6 ALIGN=MIDDLE  ALT=\"4%28x%2B4%29=2%28x%2B2%29-6\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Now solve for \"x\" to determine the first odd integer.\r<BR>\n" );
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document.write( "Remember to check the equation by substituting the values in the original equation to ensure it balances (one side of the equation equals the other). </SPAN>\n" );
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