document.write( "Question 291674: Find the critical values of the function and determine the relative max and relative min.\r
\n" ); document.write( "\n" ); document.write( "y=x^3-3x^2+6x+1\r
\n" ); document.write( "\n" ); document.write( "(I dont understand once you get the derivative how to factor it out...)\r
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Algebra.Com's Answer #210861 by richwmiller(17219)\"\" \"About 
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the derivative y=x^3-3x^2+6x+1 is 3x^2-6x+6
\n" ); document.write( "factor out 3
\n" ); document.write( "x^2-2x+2
\n" ); document.write( "there are no real roots because it never cross the x axis.(1-i and 1+i)
\n" ); document.write( "the vertex is 1,3
\n" ); document.write( "so it's low point is 3 when x=1\r
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