document.write( "Question 291550: One solution contains 50% alcohol and another solution contains 80% alcohol. How many liters of each solution should be mixed to produce 10.5 liters of a 70% alcohol solution? \n" ); document.write( "
Algebra.Com's Answer #210841 by josmiceli(19441)\"\" \"About 
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Let \"a\" = liters of 50% solution needed
\n" ); document.write( "Let \"b\" = liters of 80% solution needed
\n" ); document.write( "In words:
\n" ); document.write( "(liters of alcohol in final solution)/(total liters of final solution)
\n" ); document.write( " = 70%
\n" ); document.write( "given:
\n" ); document.write( "alcohol in 50% solution:
\n" ); document.write( "\".5a\"
\n" ); document.write( "alcohol is 80% solution:
\n" ); document.write( "\".8b\"
\n" ); document.write( "and
\n" ); document.write( "(1)\"%28.5a+%2B+.8b%29%2F10.5+=+.7\"
\n" ); document.write( "(2)\"a+%2B+b+=+10.5\"
\n" ); document.write( "----------------------
\n" ); document.write( "Multiply both sides of (1) by \"10.5\"
\n" ); document.write( "(1) \".5a+%2B+.8b+=+7.35\"
\n" ); document.write( "Multiply both sides of (2) by \".5\"
\n" ); document.write( "and subtract (2) from (1)
\n" ); document.write( "(1)\".5a+%2B+.8b+=+7.35\"
\n" ); document.write( "(2)\"-.5a+-+.5b+=+-5.25\"
\n" ); document.write( "\".3b+=+2.1\"
\n" ); document.write( "\"b+=+7\"
\n" ); document.write( "And from (2):
\n" ); document.write( "\"a+%2B+b+=+10.5\"
\n" ); document.write( "\"a+%2B+7+=+10.5\"
\n" ); document.write( "\"a+=+3.5\"
\n" ); document.write( "3.5 liters of 50% solution and 7 liters of 80% solution are needed
\n" ); document.write( "check answer:
\n" ); document.write( "(1)\"%28.5a+%2B+.8b%29%2F10.5+=+.7\"
\n" ); document.write( "(1)\"%28.5%2A3.5+%2B+.8%2A7%29%2F10.5+=+.7\"
\n" ); document.write( "\"%281.75+%2B+5.6%29%2F10.5+=+.7\"
\n" ); document.write( "\"7.35+=+10.5%2A.7\"
\n" ); document.write( "\"7.35+=+7.35\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );