document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=291546>Question 291546</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve this system of equations?\r<BR>\n" );
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document.write( "y=2x+3<BR>\n" );
document.write( "y=-2x+7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #210781 by </B><A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><B>blwinbbbles(106)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=blwinbbbles><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=210781\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You would use substitution\r<BR>\n" );
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document.write( "if y = 2x + 3 and y = -2x + 7 then you can say:\r<BR>\n" );
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document.write( "2x + 3 = -2x + 7  add 2x to both sides<BR>\n" );
document.write( "4x + 3 = 7  subtract 3 from both sides<BR>\n" );
document.write( "4x = 4  divide by 4<BR>\n" );
document.write( "x = 1\r<BR>\n" );
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document.write( "so if x = 1<BR>\n" );
document.write( "then go back to one of the original equations and put 1 in place of x<BR>\n" );
document.write( "therefore:\r<BR>\n" );
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document.write( "y = 2(1) + 3<BR>\n" );
document.write( "y = 2 + 3<BR>\n" );
document.write( "y = 5\r<BR>\n" );
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document.write( "your cordinate is (1,5)<BR>\n" );
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