document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=291537>Question 291537</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1/a-8 - 2/8-a </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #210780 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=210780\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "Let's get the common denominators 1/a-8 - 2/8-a so it would look like this:<BR>\n" );
document.write( "8/8a-(64a/8a) - 2a/8a-(8a^2/8a) This can be combined to get:<BR>\n" );
document.write( "(-8a^2-66a+8)/8a Pull out a minus 2 from the numerator to get:<BR>\n" );
document.write( "-2(4a^2-33a+4)/8a Reduce 2/8 to:<BR>\n" );
document.write( "-(4a^2-33a+4)/4a<BR>\n" );
document.write( "It was never stated what was needed with the original so I assumed you wanted it simplified.<BR>\n" );
document.write( "RJ <BR>\n" );
document.write( "www.math-unlock.com </SPAN>\n" );
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