document.write( "Question 291409: Please help me solve this. The length of a rectangular lot is 50 feet more than the width. If the perimeter is 500 feet, then what are the length and width? \n" ); document.write( "
Algebra.Com's Answer #210757 by ankor@dixie-net.com(22740)\"\" \"About 
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The length of a rectangular lot is 50 feet more than the width.
\n" ); document.write( "If the perimeter is 500 feet, then what are the length and width?
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\n" ); document.write( "2L + 2W = 500
\n" ); document.write( "Simplify, divide by 2:
\n" ); document.write( "L + W = 250
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\n" ); document.write( "\"The length of a rectangular lot is 50 feet more than the width.\"
\n" ); document.write( "L = W+50
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\n" ); document.write( "Replace L with (W+50) in the simplified equation; L + W = 250
\n" ); document.write( "(W+50) + W = 250
\n" ); document.write( "2W = 250 - 50
\n" ); document.write( "2W = 200
\n" ); document.write( "W = 100 is the width
\n" ); document.write( "and
\n" ); document.write( "100+50 = 150 is the length
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\n" ); document.write( "Check solution by finding the perimeter
\n" ); document.write( "2(150) + 2(100) = 500 \n" ); document.write( "
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