document.write( "Question 291438: Jenna walks 2 mph slower than Hampton. In the time it takes Hampton to walk 8 miles, Jenna walks 5 miles. Find the speed of each person. \n" ); document.write( "
Algebra.Com's Answer #210752 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Jenna walks 2 mph slower than Hampton.
\n" ); document.write( " In the time it takes Hampton to walk 8 miles, Jenna walks 5 miles.
\n" ); document.write( " Find the speed of each person.
\n" ); document.write( ":
\n" ); document.write( "Let s = J's walking speed
\n" ); document.write( "then
\n" ); document.write( "(s+2) = H's walking speed
\n" ); document.write( ":
\n" ); document.write( "Write a time equation: Time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "H walks 8 mi time = J walks 5 mi time
\n" ); document.write( "\"8%2F%28%28s%2B2%29%29\" = \"5%2Fs\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "8s = 5(s+2)
\n" ); document.write( ":
\n" ); document.write( "8s = 5s + 10
\n" ); document.write( ":
\n" ); document.write( "8s - 5s = 10
\n" ); document.write( ":
\n" ); document.write( "3s = 10
\n" ); document.write( ":
\n" ); document.write( "s = \"10%2F3\"
\n" ); document.write( "s = 3\"1%2F3\" mph is J's walking speed
\n" ); document.write( "then
\n" ); document.write( "5\"1%2F3\" mph is H's walking speed
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution by finding the time of each
\n" ); document.write( "8/5.33 = 1.5 hr
\n" ); document.write( "5/3.33 = 1.5 hr; confirms our solution \n" ); document.write( "
\n" );