document.write( "Question 291249: A man is nine times as old as his son. In nine years, he will only be three times as old as his son. How old are each now? \n" ); document.write( "
Algebra.Com's Answer #210651 by Fombitz(32388)\"\" \"About 
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Let M be the man's age, S be the son's.
\n" ); document.write( "Right now,
\n" ); document.write( "1.\"M=9S\"
\n" ); document.write( "In 9 years, the man will be M+9 and his son will be S+9.
\n" ); document.write( "2.\"M%2B9=3%28S%2B9%29\"
\n" ); document.write( "Substitute for M in eq. 2 using eq. 1 and solve for S.
\n" ); document.write( "\"M%2B9=3%28S%2B9%29\"
\n" ); document.write( "\"9S%2B9=3S%2B27\"
\n" ); document.write( "\"6S=18\"
\n" ); document.write( "\"S=3\"
\n" ); document.write( "Now go back to eq. 1,
\n" ); document.write( "\"M=9S\"
\n" ); document.write( "\"M=9%283%29\"
\n" ); document.write( "\"M=27\"
\n" ); document.write( "Today, the man is 27 years old and his son is 3 years old.
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