document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=291142>Question 291142</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the hypotenuse of a right triangle is 22m long the length of one leg is 10 m less than the other find the length of the legs </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #210614 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=210614\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "First let's have \"x\" be the length of one leg and the other will be x-10. Now we can plug in the values into this equation:<BR>\n" );
document.write( "a^2+b^2=c^2 <BR>\n" );
document.write( "x^2+(x-10)^2=22^2 Rewritten as:<BR>\n" );
document.write( "x^2+x^2-20x+100=484 Subtract 484 from both sides to get:<BR>\n" );
document.write( "2x^2-20x-384=0 We'll need to use the Quadratic Formula so <BR>\n" );
document.write( "plug the values into this: <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "I'll let you do the rest from here. <BR>\n" );
document.write( "RJ <BR>\n" );
document.write( "www.math-unlock.com </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );