document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=291143>Question 291143</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This is a Solving by substution x+2y =8 and 2x+y =8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #210609 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=210609\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "Let's do this: x+2y =8 and 2x+y =8 Rewrite the first equation to look like:<BR>\n" );
document.write( "x =8-2y and plug this into the second equation to get:<BR>\n" );
document.write( "2(8-2y)+y=8 rewritten will be:<BR>\n" );
document.write( "16-4y+y=8 Combine like terms and subtract 16 from both sides to get:<BR>\n" );
document.write( "-3y=-8 Then:<BR>\n" );
document.write( "y=8/3 <BR>\n" );
document.write( "Plug this answer into the original and we get:<BR>\n" );
document.write( "x=8/3<BR>\n" );
document.write( "Make sense?<BR>\n" );
document.write( "There's a book I wrote on the basics <BR>\n" );
document.write( "www.math-unlock.com <BR>\n" );
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