document.write( "Question 291095: The perimter of a rectangle is 174 inches. The elngth exceeds the width by 61 inches. What is the length and the width?
\n" ); document.write( "What is the lenghth?______
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\n" ); document.write( "What is the width?_____
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Algebra.Com's Answer #210603 by brucewill(101)\"\" \"About 
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Let x = width
\n" ); document.write( "Therefore, x + 61 = length.\r
\n" ); document.write( "\n" ); document.write( "Permiter requires 2 each of width & length.\r
\n" ); document.write( "\n" ); document.write( "2x + 2(x + 61) = 174
\n" ); document.write( "2x + 2x + 122 = 174
\n" ); document.write( "4x = 52
\n" ); document.write( "\"highlight%28x+=+13%29\" width
\n" ); document.write( "Therefore, 13 + 61 = 74 length.\r
\n" ); document.write( "\n" ); document.write( "Check: 13 + 74 + 13 + 74 = 174. OK.
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