document.write( "Question 291095: The perimter of a rectangle is 174 inches. The elngth exceeds the width by 61 inches. What is the length and the width?
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document.write( "What is the lenghth?______
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document.write( "(Type and integer or a decimal)
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document.write( "What is the width?_____
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document.write( "( type and integer or a decimal) \n" );
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Algebra.Com's Answer #210603 by brucewill(101)![]() ![]() ![]() You can put this solution on YOUR website! Let x = width \n" ); document.write( "Therefore, x + 61 = length.\r \n" ); document.write( "\n" ); document.write( "Permiter requires 2 each of width & length.\r \n" ); document.write( "\n" ); document.write( "2x + 2(x + 61) = 174 \n" ); document.write( "2x + 2x + 122 = 174 \n" ); document.write( "4x = 52 \n" ); document.write( " \n" ); document.write( "Therefore, 13 + 61 = 74 length.\r \n" ); document.write( "\n" ); document.write( "Check: 13 + 74 + 13 + 74 = 174. OK. \n" ); document.write( " \n" ); document.write( " |