Algebra.Com's Answer #210596 by jim_thompson5910(35256)![\"\"](\"/images/stars/stars-13.gif\")  
You can put this solution on YOUR website!
You're on the right track. I'll start where you left off.\r
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document.write( "Let's solve  by use of the quadratic formula.\r
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document.write( " | Solved by pluggable solver: Quadratic Formula | \n" );
document.write( "Let's use the quadratic formula to solve for x:
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document.write( " Starting with the general quadratic
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document.write( " the general solution using the quadratic equation is:
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document.write( " So lets solve  ( notice  ,  , and  )
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document.write( "  Plug in a=13, b=65, and c=78
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document.write( "  Square 65 to get 4225
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document.write( "  Multiply  to get 
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document.write( "  Combine like terms in the radicand (everything under the square root)
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document.write( "  Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
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document.write( "  Multiply 2 and 13 to get 26
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document.write( " So now the expression breaks down into two parts
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document.write( "  or 
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document.write( " Lets look at the first part:
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document.write( "  Add the terms in the numerator
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document.write( "  Divide
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document.write( " So one answer is
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document.write( " Now lets look at the second part:
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document.write( "  Subtract the terms in the numerator
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document.write( "  Divide
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document.write( " So another answer is
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document.write( " So our solutions are:
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document.write( " or
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document.write( "Now plug each of these solutions into  to find the corresponding 'y' coordinates of the intersections. \r
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document.write( "So when , then  giving us the point (-2,3)\r
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document.write( "Also, when , then  giving us the point (-3,-2)\r
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document.write( "So the two points of intersection are (-2,3) and (-3,-2)\r
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