document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=291021>Question 291021</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a triangle is 81 cm. The smallest side is 7cm.shorter than the medium side. The medium side is 4 cm.shorter than the longest side. Find the lengths of the three sides. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #210568 by </B><A HREF=/tutors/aboutme.mpl?userid=Greenfinch><B>Greenfinch(383)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Greenfinch><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Greenfinch><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=210568\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Shortest side is X, medium side is X + 7, longest side is X + 11<BR>\n" );
document.write( "perimeter is X + (X + 7) + ( X + 11) =3X + 18 = 81<BR>\n" );
document.write( "So 3X= 63<BR>\n" );
document.write( "X = 21, other sides are 28 and 32 <BR>\n" );
document.write( "perimeter is 21 + 28 + 32 = 81 so it checks </SPAN>\n" );
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