document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=291045>Question 291045</A>: <I><SPAN STYLE=\"word-break: break-all;\"> audrey has 35 dimes and quarters in her piggy bank with a total value of 6.95. How many of the coins are dimes and how many are quarters? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #210561 by </B><A HREF=/tutors/aboutme.mpl?userid=Greenfinch><B>Greenfinch(383)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Greenfinch><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Greenfinch><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=210561\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Not being American, i assume a dimes is 10 cents and a quarter is 25 cents.<BR>\n" );
document.write( "There are 35 coins, so call the number of quarters X and the number of dimes 35 -X<BR>\n" );
document.write( "The equation is then 25X + 10(35 - X) = 695  (Do it all in cents)<BR>\n" );
document.write( "25X + 350 - 10X = 695<BR>\n" );
document.write( "15X = 345<BR>\n" );
document.write( "X= 23<BR>\n" );
document.write( "So there should be 23 quarters and 12 dimes<BR>\n" );
document.write( "Check 23 x 25 + 12 x 10 = 575 + 120 = 695 </SPAN>\n" );
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