document.write( "Question 290789: Rodgers age is 1 and 1/3 times Stevens age. Eight years ago, Rodger's age was twice Steven's age. Find Rodger's age \n" ); document.write( "

Algebra.Com's Answer #210484 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Rodgers age is 1 and 1/3 times Stevens age.
\n" ); document.write( "r = $\"4%2F3\"$ s
\n" ); document.write( "multiply by 3
\n" ); document.write( "3r = 4s
\n" ); document.write( "4s = 3r
\n" ); document.write( "s = $\"3%2F4\"$ r
\n" ); document.write( ":
\n" ); document.write( "Eight years ago, Rodger's age was twice Steven's age.
\n" ); document.write( "r - 8 = 2(s-8)
\n" ); document.write( "r - 8 = 2s - 16
\n" ); document.write( "r = 2s - 16 + 8
\n" ); document.write( "r = 2s - 8
\n" ); document.write( ":
\n" ); document.write( "Find Rodger's age
\n" ); document.write( ":
\n" ); document.write( "Replace s with $\"3%2F4\"$ r in the above equation
\n" ); document.write( "r = 2( $\"3%2F4\"$ r) - 8
\n" ); document.write( "r = $\"6%2F4\"$ r - 8
\n" ); document.write( "Multiply equation by 4, results
\n" ); document.write( "4r = 6r - 32
\n" ); document.write( "32 = 6r - 4r
\n" ); document.write( "32 = 2r
\n" ); document.write( "r = $\"32%2F2\"$
\n" ); document.write( "r = 16 yrs is Roger's age
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution:
\n" ); document.write( "s = $\"3%2F4\"$ (16)
\n" ); document.write( "s = 12
\n" ); document.write( "\"Eight years ago, Rodger's age was twice Steven's age.\"
\n" ); document.write( "16 - 8 = 2(12-8)
\n" ); document.write( "8 = 2(4)
\n" ); document.write( " \n" ); document.write( "

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