document.write( "Question 290872: a 20% ammonia solution and a 5% ammonia solution are to be mixed to obtain 50 gallons of an 8% solution. how much of each should be used fill out a tabel \n" ); document.write( "
Algebra.Com's Answer #210481 by checkley77(12844)\"\" \"About 
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.20X+.05(50-X)=.08*50
\n" ); document.write( ".20X+2.5-.05X=4
\n" ); document.write( ".15X=4-2.5
\n" ); document.write( ",15X=1.5
\n" ); document.write( "X=1.5/.15
\n" ); document.write( "X=10 GAL. OF 20% SOLUTION IS NEEDED.
\n" ); document.write( "50-10=40 GAL. OF 5% SOLUTION IS NEEDED.
\n" ); document.write( "PROOF:
\n" ); document.write( ".20*10+.05*40=.08*50
\n" ); document.write( "2+2=4
\n" ); document.write( "4=4
\n" ); document.write( "
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