document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=290830>Question 290830</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to solve for x here but I'm not sure how to go about that in this problem.<BR>\n" );
document.write( "log(2x)=log(x+9)Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #210467 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=210467\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log(2x) = log(x+9)<BR>\n" );
document.write( "You should note that if log(2x) = log(x+9), then<BR>\n" );
document.write( "2x = x + 9<BR>\n" );
document.write( "2x - x = 9<BR>\n" );
document.write( "x = 9<BR>\n" );
document.write( ":<BR>\n" );
document.write( "If you substitute 9 for x in the original problems, you have:<BR>\n" );
document.write( "log(2*9) = log(9+9)<BR>\n" );
document.write( "log(18) = log(18), obviously </SPAN>\n" );
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