document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=290807>Question 290807</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a jar containing only nickels and dimes contains 60 coins. The value of all the coins in the jar is $4.45. solve by elimination to find the amount of nickels and dimes are in the jar<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #210456 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=210456\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> N+D=60 MULTIPLY THIS EQUATION BY -.05 & ADD<BR>\n" );
document.write( ".05N+.10D=4.45<BR>\n" );
document.write( "-.05N-.05D=-3<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( ".05D=1.45<BR>\n" );
document.write( "D=1.45/.05<BR>\n" );
document.write( "D=29 DIMES.<BR>\n" );
document.write( "60-29=31 NICKELS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( ".05*31+.10*29=4.45<BR>\n" );
document.write( "1.55+2.90=4.45<BR>\n" );
document.write( "4.45=4.45 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );