document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=290798>Question 290798</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is twice the width of the rectangle. The length of a diagonal of the rectangle is 25cm. How do I find out the are of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #210421 by </B><A HREF=/tutors/aboutme.mpl?userid=Greenfinch><B>Greenfinch(383)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Greenfinch><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Greenfinch><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=210421\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the width is X, the length is 2X and the diagonal is sqrt ((X^2) + (2X)^2)<BR>\n" );
document.write( "So sqrt(5X^2) = 25 or 5X^2 = 625<BR>\n" );
document.write( "X^2 = 125<BR>\n" );
document.write( "Area is X x 2X = 2X^2 = 250 </SPAN>\n" );
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