document.write( "Question 290790: Amy is twice as old as Jenny. Five years ago, Amy was three times as old as Jenny. Find Jenny's age. \n" ); document.write( "

Algebra.Com's Answer #210416 by Deina(147) $\"\"$ $\"About$

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Amy = A
\n" ); document.write( "Jenny = J

\n" ); document.write( " $\"+A+=+2J+\"$ so $\"+A+-+2J+=+0+\"$

\n" ); document.write( " $\"+A-5+=+3%28J-5%29+\"$

\n" ); document.write( " $\"+A-5+=+3J+-+15+%2B+5+\"$

\n" ); document.write( " $\"+A-3J+=+-10+\"$

\n" ); document.write( "

\n" ); document.write( "Since:
\n" ); document.write( " $\"+A+-+2J+=+0+\"$

\n" ); document.write( " $\"+A-3J+=+-10+\"$

\n" ); document.write( "So -J = -10 therefore J = 10

\n" ); document.write( "Now we've found that Jenny is ten, and since Amy is twice as old:
\n" ); document.write( "Jenny = 10, Amy = 20
\n" ); document.write( "and bob's your uncle!
\n" ); document.write( " \n" ); document.write( "

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