document.write( "Question 290748: x/2 + 1/x-1 = x/x-1\r
\n" ); document.write( "\n" ); document.write( "thank you for the help for solving this equation.
\n" ); document.write( "

Algebra.Com's Answer #210373 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve for x:
\n" ); document.write( "\"%28x%2F2%29%2B%281%2F%28x-1%29%29+=+x%2F%28x-1%29\" The lowest common denominator (LCD) is: \"2%28x-1%29\", so...
\n" ); document.write( "\"%28x%28x-1%29%2F2%28x-1%29%29%2B2%2F%282%28x-1%29%29+=+2x%2F%282%28x-1%29%29\" Multiply through by \"2%28x-1%29\" to clear the fractions.
\n" ); document.write( "\"x%28x-1%29%2B2+=+2x\" Simplify.
\n" ); document.write( "\"x%5E2-x%2B2+=+2x\" Subtract 2x from both sides.
\n" ); document.write( "\"x%5E2-3x%2B2+=+0\" Solve by factoring.
\n" ); document.write( "\"%28x-1%29%28x-2%29+=+0\" Apply the zero product rule.
\n" ); document.write( "\"x-1+=+0\" or \"x-2+=+0\" so...
\n" ); document.write( "\"x+=+1\" or \"x+=+2\"
\n" ); document.write( "However, notice that when you substitute x = 1 into the given equation, you will get undefined terms:
\n" ); document.write( "\"%28x%2F2%29%2B%281%2F%28x-1%29%29+=+x%2F%28x-1%29\" Substitute x = 1.
\n" ); document.write( "\"%281%2F2%29%2B%281%2F%281-1%29%29+=+1%2F%281-1%29\" or...
\n" ); document.write( "\"%281%2F2%29%2B1%2F0+=+1%2F0\" but \"1%2F0\" is undefined, so x = 1 is an excluded solution.
\n" ); document.write( "Answer: \"highlight%28x+=+2%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" );